*
* Example 2/7/2 from pp 67-68
*
open data milk.dat
calendar(m) 1969
data(format=free,org=columns) 1969:1 1982:11 milk
*
graph(footer="Monthly milk production per cow")
# milk
*
* The %DAYCOUNT function returns the number of days in an entry (in this case, a
* month).
*
set adjusted = milk*(365.25/12.0)/%daycount(t)
graph(footer="Adjusted monthly milk production per cow")
# adjusted